Resolve Pascal’s Triangle in Python

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The problem

Given an integer numRows, return the primary numRows of Pascal’s triangle.

In Pascal’s triangle, every quantity is the sum of the 2 numbers straight above it as proven:

Instance 1:

Enter: numRows = 5
Output: [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]

Instance 2:

Enter: numRows = 1
Output: [[1]]

Constraints:

The answer in Python code

class Answer:
    def generate(self, numRows: int) -> Listing[List[int]]:
        triangle = [[1]]
        
        for j in vary(1, numRows):
            prev = triangle[-1]
            triangle.append([1] + [prev[i]+prev[i+1] for i in vary(len(prev)-1)] + [1])
            
        return triangle

Code language: Python (python)

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